Δjkl has j = 7, k = 11, and m∠j = 18°. complete the statements to determine all possible measures of angle k. triangle jkl meets the criteria, which means it is the ambiguous case. substitute the known values into the law of sines: . cross multiply: 11sin(18°) = . solve for the measure of angle k, and use a calculator to determine the value. round to the nearest degree: m∠k ≈ °. however, because this is the ambiguous case, the measure of angle k could also be °.

K = 29°

The triangle is ΔJKL. Therefore,

m∠J = 18°

m ∠ K = ?

j = 7

k = 11

To find m ∠ K we can use sine rule, Therefore,

j / sin 18° = k / sin K

7 / sin 18°  = 11 / sin K

cross multiply

7 sin k  = 11 sin 18°

sin K = 3.39918693812  / 7

sin K = 0.48559813401

K = sin ⁻¹ 0.48559813401

K = 29.0516591712

K ≈ 29°

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step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %