In a sample of 10 cards, 4 are red and 6 are blue. if 2 cards are selected at random from the sample, one at a time without replacement, what is the probability that both cards are not blue?

The probability of both the cards not being blue would be:

-

Given that,

Total cards = 10

No. of Red Cards = 4

No. of Blue cards = 6

The probability of not picking a blue card = 4/10     (∵ 4 are red)

As we know,

2 cards are picked at random,

In case,

The cards picked are not replaced, the possible chances of taking red would be = 3/9

Now,

The Probability of not picking a blue card(P) = no. of favorable outcomes/total outcomes

×

××

By solving,

12/90

××

Thus, 2/15 or 0.1333 is the correct answer.

Learn more about 'Probability' here:

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if im undersanding the question correctly, its organized from 10

step-by-step explanation:

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!