Mathematics, 16.07.2019 12:30 jhjhgjvygv
Where are the x-intercepts for f(x) = −4cos(x − pi over 2) from x = 0 to x = 2π?
Answers: 1
![\bf \stackrel{f(x)}{0}=-4cos\left(x-\frac{\pi }{2} \right)\implies 0=cos\left(x-\frac{\pi }{2} \right) \\\\\\ cos^{-1}(0)=cos^{-1}\left[ cos\left(x-\frac{\pi }{2} \right) \right]\implies cos^{-1}(0)=x-\cfrac{\pi }{2} \\\\\\ x-\cfrac{\pi }{2}= \begin{cases} \frac{\pi }{2}\\\\ \frac{3\pi }{2} \end{cases}](/tpl/images/0096/3365/fec9b.png)
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Where are the x-intercepts for f(x) = −4cos(x − pi over 2) from x = 0 to x = 2π?...
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