Find the length of the hypotenuse of a right triangle whose legs like 3 and squared root 2○2square root 2○square root 11○square root 13

Find the length of the hypotenuse of a right triangle whose leg lengths are 3 and square root 2:

Use the Pythagorean Theorem here.  Square 3 and square [sqrt(2)], and then find the sqrt of the sum:  9 + 2 = 11.

The hyp. length is then +sqrt(11).

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0