Which absolute value function, when graphed, will be narrower than the graph of the parent function f(x)=|x|

Hello!

The parent function is f(x)=|x| if you want a function g(x) that has a graph narrower than the graph of f(x), then the slope of g(x) must be greater than 1.

where g(x) has the form: f(x) = |ax| where a is a real number, and particularly in this case, greater than one, then an example of this can be if we took an equal to 2, then:

g(x) = |2x| is a function that has a graph narrower than the graph of the parent function.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.