Michael is organizing a game of chance for his class. he asks each student to pick a ribbon from a bag and then put it back into the bag. the bag has 12 yellow ribbons, 7 red ribbons, and 3 blue ribbons. if jane picks a ribbon, what is the probability that the ribbon will be yellow and what is the likelihood of this event? a. the probability is 1, and the event is certain. b. the probability is 3/11 , and the event is likely. c. the probability is 6/11 , and the event is unlikely. d the probability is 6/11 , and the event is neither likely nor unlikely.

Hello there!

We know that the bag has:

12 yellow ribbons, 7 red ribbons, and 3 blue ribbons.

this is a total of 22 ribbons.

The probability of picking a yellow ribbon is equal to the number of yellow ribbons divided by the total amount of ribbons:

this is 12/22, that can be simplified to 6/11

6/11 is equal to 0.545

this is equivalent to 54.5%, then this an almost even chance, so is neither likely or unlikely.

Then the right answer is option D "The probability is 6/11, and the event is neither likely nor unlikely."

1

step-by-step explanation:

it's the only multiple of both and the least

5/12, or 5: 12

step-by-step explanation: