Math i will givetwo urns contain white balls and yellow balls. the first urn contains 8 white balls and 8 yellow balls and the second urn contains 10 white balls and 3 yellow balls. a ball is drawn at random from each urn. what is the probability that both balls are white? 3/26 13/28 1/13 5/13

The first urn has 8 white balls and 8 yellow balls
There are 16 balls in all, in which 8 are white.

8/16, or 1/2, is the probability from the first urn.

The second urn has 10 white balls and 3 yellow balls
There are 13 balls in all, in which 10 are white

10/13, is the probability from the second urn.

multiply the two fractions together: 

10/13 x 1/2 = 10/26

10/26 simplified = 5/13

5/13, or D is your answer

hope this helps

Hello!

To find the probability of the compound event, we multiply the probabilities of the two separate events, pulling white balls from the first and second urns.

In the first urn, there are eight white and eight yellow. This means that there are 16 total balls. This means we have an 8/16, or 1/2 chance of selecting a white ball.

In the second urn, there are 10 white and three yellow balls. This means there are 13 total balls. This gives us the probability 10/13.

Finally, we will need to multiply the two probabilities. 1/2(10/13)=5/13.

Our final answer is D) 5/13.

I hope this helps!

We need more info then that