What is the domain of the function?

(2, ∞)

Step-by-step explanation:

The function is not defined to the left of x=2 (assuming the independent variable is x). There is a vertical asymptote at x=2, so the function is not actually defined for x=2. However, the function is defined for all values of the independent variable greater than 2, so that is its domain.

(We don't actually know what the indpendent variable is, so we have expressed the domain in interval notation—avoiding the problem of naming the independent variable.)

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb