Use the parabola tool to graph the quadratic function f(x)=(x−2)(x−6) . graph the parabola by first plotting its vertex and then plotting a second point on the parabola.

Where's the so-called "parabola tool?"

The vertex is relatively easy to find.  Find the midpoint of the segment of the x-axis connecting x=2 and x=6; it is x=4.  Then evaluate the function at x=4:

f(4) = (4-2)(4-6) = 2(-2) = -4.  The vertex is at (4,-4).

Plot (4,-4).  Then (arbitrarily) let x=0 and find y:  f(0) = y = (-2)(-6) = -12.
So, when x = 0, y = -12.

Plot this point (1, -12).  realize that the parabola is symmetric about the line x=4.  (1,-12) is 3 units to the left of the axis of symm, and thus another point on the parab. is 3 units to the right of this axis, x= 7.  Plot (7,-12).  Now draw the parabola thru (7,-12), (1, -12) and (4, -4).  The parab. opens up.

The answer to your question is b’(16,14)