solve the obove questions

        for    0°≤x≤360°answer and explanationthe answers are    x = 0°, 30°, 150°, 180°, 360°this can be solved using trigonometric identities.notice that we have a first-power sine term.the terms cos(2x) and cos²x all have some sort of identity that can change them into something with sine. therefore, it will be useful to have everything as sine.the pythagorean identity links cos²x and sin²x via the identity    sin²x + cos²x = 1    ⇒ cos²x = 1 - sin²xthat allows us to convert cosine square into sine squareda cosine double identity to use:       cos(2x) = 1 - 2sin²xnow we can convert everything in terms of sine:     subtracting 1 from both sides results in      get rid of the 2sin²x term on the leftadding 2sin²x to both sides results in    subtracting (1/2)sin x from both sides results in    factor out sin x    we have one side of the equation fully factored and the other side equal to zero.therefore, either sin x = 0 or sin x - 1/2 = 0 because zero times anything is zero (zero factor property). solving the first one    sin x = 0in a unit circle, sine is defined as the ratio of the y-coordinate of the point of intersection of the terminal arm to the radiusby the unit circle, the solutions, for 0°≤ x  ≤ 360°, include 0°, 180°, and 360° (y-coordinate is 0 for those angles)solving the other equation:     sin x - 1/2 = 0move and you get sin x = 1/2. by the unit circle, the solutions include 30° and 150°thus the final solution is    x = 0°, 30°, 150°, 180°, 360°you can test all this in the original equation and all of them will work