In how many ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other?

The 5 people can seat in a row in 5! ways
But we need to exclude the ways that ann and bob are seated next to each other which is = 4! * 2!

So, the number of ways can ann, bob, chuck, don and ed be seated in a row such that ann and bob are not seated next to each other = 5! - 4! * 2! = 72



Another solution:

If ann seated in one of the ends, the number of ways = 3*2

If ann didn't seat in one of the ends , the number of ways = 2*3

So, the total number of ways that can ann, bob be seated = 3*2 + 2*3 = 12

The remaining persons can seat with a number of ways = 3! = 6
So, the total ways that the five persons can seat = 12*6 = 72

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