Two cars traveled equal distances in different amounts of time. car a traveled the distance in 2.4 h, and car b traveled the distance in 4 h. car a traveled 22 mph faster than car b. how fast did car a travel? mph

Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B

Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)

plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB

remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph

vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph

$79500

step-by-step explanation:

75000÷100=750750×106=79500

1.) 18+5 is one way i’m pretty sure there are others but i can’t think of them right now