Pls if you can a savings account pays 2% interest compounded annually. if $1,200 is deposited initially and again at the first of each year, how much money will be in the account three years after the initial deposit? $1,248.48 $2,472.48 $3,672.48 $3,745.93

It would be $3,745.93.

Step-by-step explanation:

Given,

$ 1200 is deposited first year that earns 2 % interest compounded annually,

⇒ The amount of first deposit after 3 years would be,

Now, $ 1200 is deposited second year that earns 2 % interest compounded annually,

⇒ The amount of second deposit after 2 years would be,

Also, Again $ 1200 is deposited third year that also earns 2 % interest compounded annually,

⇒ The amount of third deposit after 1 year would be,

Hence, the total money in the account after three years,

Last option is correct.

goog may have it for you

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3