What is the area of a right triangle with a hypotenuse of 12 and 1 leg is 10? ?

Hey there! :)

Area of triangles → (base × height) ÷ 2

The base and height are the 2 legs. You have to find the length of the other leg to find the area, using the Pythagorean Theorem.

a² + b² = c² → c² - a² = b²

c = 12
12² = 12 × 12 = 144

a = 10
10² = 10 × 10 = 100

144 - 100 = 44

√44 = 6.6


Area of triangles → (base × height) ÷ 2

Base: 10
Height: 6.6

6.6 × 10 = 66

66 ÷ 2 = 33

The area is 33 

Hope this helps :)