Two triangles can be formed with the given information. use the law of sines to solve the triangles. a = 56°, a = 12, b = 14

We know that
case 1)
Applying the law of sines
a/Sin A=b/Sin B
A=56°
a=12
b=14
so
a*Sin B=b*Sin A> Sin B=b*Sin A/a---> Sin B=14*Sin 56°/12
Sin B=0.9672
B=arc sin (0.9672)> B=75.29°> B=75.3°

find angle C
A+B+C=180°> C=180-(A+B)> C=180-(56+75.3)> C=48.7°

find c
a/Sin A=c/Sin C> c=a*Sin C/Sin A> c=12*Sin 48.7°/Sin 56°)
c=10.87> c=10.9

the answer Part 1)
the dimensions of the triangle N 1
are
a=12  A=56°
b=14  B=75.3°
c=10.9  C=48.7°

case 2) 
A=56°
a=12
b=14
B=180-75.3> B=104.7°

find angle C
A+B+C=180°> C=180-(A+B)> C=180-(56+104.7)> C=19.3°

find c
a/Sin A=c/Sin C> c=a*Sin C/Sin A> c=12*Sin 19.3°/Sin 56°)
c=4.78> c=4.8

the answer Part 2)
the dimensions of the triangle N 2
are
a=12  A=56°
b=14  B=104.7°
c=4.8    C=19.3°