Can you me out on this question posted picture

When atleast one dice shows a 6 the possible outcomes will be:
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
(1,6), (2,6), (3,6), (4,6), (5,6)

Thus there are 11 total possible outcomes.

Among these outcomes, the sum of numbers greater than or equal to 9 can be obtained from:
(6,3), (6,4), (6,5), (6,6), (3,6), (4,6), (5,6)

This means there are 7 outcomes with sum greater than or equal to 9. 

Thus, Probability of rolling a number greater than or equal to 9 with atleast one dice showing a 6 = 9/11

So, option A gives the correct answer

Are there any statements?

Ibelieve that c. recording would work best.