The graph of the function g(x) = x2 + 3x - 4 is shifted 5 units to the left. plot the zeros of the new function on the provided graph.

g(x) = x^2 + 3x - 4   (please be sure to use " ^ " to denote exponentiation).

This function factors into g(x) = (x+4)(x-1), and so the zeros are -4 and +1.

If we shift this graph 5 units to the left, we get h(x) = (x+5)^2 + 3(x+5) - 4.

The new zeros will be -4-5    and    1-5,    or  -9 and -4.

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I'm not sure exactly but my best guess would be 1/4