At the beginning of year 1, bode invests $250 at an annual simple interest rate of 3%. he makes no deposits to or withdrawals from the account. which explicit formula can be used to find the account’s balance at the beginning of year 14? what is the balance? a. a(n) = (250)(n – 1)(0.03); $97.50 b. a(n) = 250 + (n)(0.03 • 250); $355.00 c. a(n) = 250 + (n – 1)(0.03); $250.39 d. a(n) = 250 + (n – 1)(0.03 • 250); $347.50

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier