The chance that you make a three-point shot in a basketball game is 30%. how many three-point shots would you expect to make if you took 50 shots?

So 3 in every 10 would make it because 30% equals 3/10 and since there are 50 that would be 5 sets of 10. Thus 3*5=15. You would make 15 shots

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

55. i don’t no. but zhongshan