Identify the vertical asymptote(s) of each function. check all of the boxes that apply. f(x)=3x/x^2-16 answers: x = -16 x = -4 x = 0 x = 4 x = 16

The vertical asymptotes of a function corresponds to the zeros of the denominator of the function.

The vertical asymptotes are: x = 4 and x = -4

The function is given as:

Equate the denominator to 0

Express 16 as 4^2

Express as difference of two squares

Split

Solve for x

Hence, the vertical asymptotes are: x = 4 and x = -4

Read more about vertical asymptotes at:

link

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .