Let a=x^2+4. rewrite the following equation in terms of a. (x^2+4)^2+32=12x^2+48 in resulting equation what is the coefficient of the a term in the resulting equation, what is the constant

We're given:


And with that we must rewrite the equation  in terms of .

Currently, the equation is written in terms of , so lets start by writing in terms of :



Now lets replace every in by : 




Now that we have the equation in terms of , lets equal it to 0:





So the equation (in terms of ) is written in a standard form as .

We can clearly see that the coefficient of is -12 and the constant is 32.