Guys i really need with this question asap !

Any line parallel to the given line will have the same slope as does the given line.  Here that slope is -9.

The new line passes thru (-2,5).

Therefore, using the slope-intercept form,

5 = -9(-2) + b.  Find b:  5 = 18 + b, so b = -13.  The equation of the new, parallel line is then

y = -9x - 13    (answer to first question).

If you want the slope of a line perpendicular to the given line, use the "negative reciprocal" of the slope of the given line as the slope of the new, perpendicular line.  Thus, the new slope will be -1/(-9), or (+1/9).

Use the slope-intercept form, with slope = (1/9), to find the line perpendicular to the given line that passes thru the given point.  Share your work, please.

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