Find an equation in standard form for the hyperbola with vertices at (0, ±6) and asymptotes at y = ±3 divided by 2.x

The equation of hyperbola with vertices at (0,±6) and asypmtotes at

Step-by-step explanation:

Given

vertices of hyperbola at (0,±6)

It means hyperbola along y axis and centre at (0,0)

Asymptotes

We know that equation of hyperbola along y axis

a=6

We know that the general equation of hyperbola asymptotes and vertcal transverse axis

    y=

 =

Both side cancel x we get

b=4

When we take }{b}x" alt="b=\frac{-6\times (-2)}{3}" />}{b}x" />

Then we get b=4

Now, put the value of a and b in the equation of hyperbola we get

=1

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

mnkjn

step-by-step explanation: