Alanna is painting a border on a wall. the border consists of kite-shaped figures as shown. mc022-1.jpg each kite measures 6 inches across and 12 inches long. the wall is 12 feet across. how many square inches of the wall will be covered with kites? 216 432 864 1,728

the question does not present the picture, but this does not interfere with the resolution

step 1

Find the area of a kite

we know that

area of a kite=(1/2)*[d1*d2]

where d1 and d2 are the diagonals

so 

area of a kite=(1/2)*[6*12]> 36 in²

The wall is 12 feet across> convert to in> 12*12> 144 in

step 2
find the number of kite to paint
divide across of the wall to across of a kite
144/6> 24 

step 3
find the number of square inches of the wall to be covered with comets
24*area of one kite> 24*36> 864 in²

the answer is 864 in²
Note For this calculation, as there is no drawing we have assumed that the diagonal of the 6-inch kite is horizontal

case b) 
If the diagonal of the 12-inch kite was horizontal, then the calculation would be
step 2
find the number of kite to paint
divide across of the wall to across of a kite
144/12> 12

step 3
find the number of square inches of the wall to be covered with comets
12*area of one kite> 12*36> 432 in²

the answer would be 432 in²

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer