Consider the means of the samples shown in the table. which value is least likely to be the mean of the population from which the samples were taken? sample//sample mean .2 2 .1 3 .9 4 .2 .0 6 .3 7 .4 a.12.2 b.15.3 c.16.4 d.17.5

If we ignore   4 12.2, we have a list of 6 means ranging from 16.9 to 18.0.  It's reasonable to state that "12.2 is significantly lower than each of the other means."  Thus, 12.2 is least likely to be the mean of the population from which the samples were taken.
 

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.