Hi, asap~(no one is me ; -; ) + janelle is at the movie theater and has $20 to spend. she spends $8 on a ticket and wants to buy some snacks. each snack costs $4.99 . how many snacks, x , can janelle buy? inequality that represents this situation: 20≥8+4.99x drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution

Part A : 2 snacks

Part B : Solution to both the inequality and the problem situation ⇒ 1 , 2

             Solution to the inequality only ⇒ -4 , 3/4 , 2.3

             Not a solution ⇒ 2.5

Step-by-step explanation:

Part A :

Janelle  has $20 to spend

She spends $8 on a ticket, so , the remaining = 20 - 8 = $12

Each snack costs $4.99

So, the number of snacks =

the integer of ( 12 / 4.99 ) = integer of (2.4) = 2 snacks

Part B:

Inequality that represents this situation: 20 ≥ 8 + 4.99x

Solve for x

∴ 20 - 8 ≥ 4.99 x

12 ≥ 4.99 x

divide both sides by 4.99

∴ (12/4.99) ≥ x

∴ x ≤ 2.4048

The given options are : -4 , 3/4 , 2.3 , 2.5 , 1 , 2

So,

Solution to both the inequality and the problem situation ⇒ 1 , 2

solution to the inequality only ⇒ -4 , 3/4 , 2.3

Not a solution ⇒ 2.5

sine

step-by-step explanation: