Use the discriminant to determine the nature of the roots of the following equation. y^2 - 5y - 3 = 0

Here a=1, b= -5 and c= -3

so the discrim. is b^2 - 4(a)(c),   or   (-5)^2 - 4(1)(-3)  = 25 + 12 = 37.

Because the discrim. is +, you'll have 2 real, unequal roots.

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*