Circle 1 is centered at (5, 8) and has a radius of 8 cm. circle 2 is centeted at (1,-2) and has a radius of 4cm. what transformation rule can be applied to circle 1 to prove that the circles are similar? the circles are similar because you can translate circle 1 using the translation and the dialate it using a scale factor

we know that
Figures can be proven similar if one, or more, similarity transformations (reflections, translations, rotations, dilations) can be found that map one figure onto another. 
In this problem to prove circle 1 and circle 2 are similar, a translation and a scale factor (from a dilation) will be found to map one circle onto another.

we have that
 Circle 1 is centered at (5,8) and has a radius of 8 centimeters
 Circle 2 is centered at (1,-2) and has a radius of 4 centimeters

step 1
Move the center of the circle 1 onto the center of the circle 2
the transformation has the following rule
(x,y)> (x-4,y-10)
so
(5,8)> (5-4,8-10)> (1,-2)
so
center circle 1 is now equal to center circle 2 
The circles are now concentric (they have the same center)

step 2
A dilation is needed to decrease the size of circle 1 to coincide with circle 2

scale factor=radius circle 2/radius circle 1> 4/8> 0.5

radius circle 1 will be=8*scale factor>8*0.5> 4 cm
radius circle 1 is now equal to radius circle 2 

A translation, followed by a dilation will map one circle onto the other, thus proving that the circles are similar

the answers are 

a) The circles are similar because you can translate circle 1 using the translation rule

(x,y)> (x-4,y-10)

b) And the dilate it using a scale factor of 0.5

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step-by-step explanation:

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.