In the given parallelogram your angle your, ruo is 120 degree and a oy is extended to the point as such that angle s r y is equal to 50 degree find angle ysr

70°

Step-by-step explanation:

Given,

YOUR is a parallelogram,

In which ∠RUO = 120°,

∠SRY = 50°,

To find : ∠YSR  

Since, the opposite angles of a parallelogram are equal.

⇒ ∠RUO = ∠RYO

⇒ ∠RYO = 120°,

Also, ∠RYO and ∠RYS are linear pairs,

⇒ ∠RYO + ∠RYS = 180°,

⇒ 120° + ∠RYS = 180°,

⇒ ∠RYS = 60°,

Now, In triangle RSY,

∠YSR + ∠RYS + ∠SRY = 180°,

∠YSR + 60° + 50° = 180°

∠YSR = 180° - 110° = 70°

d 192

step-by-step explanation:

we find our area to find area we multiply thoses numbers to get our answer so our area is 192

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.