Write an equation of the ellipse with foci at (0,+12) and vertices at (0,+13)

 To solve this problem you must apply the proccedure shown below:
 1. You have that the ellipse given as a vertical major axis (a=13), therefore, taking the ellipse with its center at the origin, you have the following equation:
 (y^2/a^2)+(x^2/b^2)=1
 2. You have the distance from the center of the ellipse to the focus:
 c=12, therefore, you can calculate the value of b, the minor radius:
 c^2=a^2-b^2
 b=√(13^3-12^2)
 b=5
 3. Therefore, the equation is:
 a^2=169
 b^2=25
 (y^2/169)+(x^2/25)=1
 The answer is: (y^2/169)+(x^2/25)=1 

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