If the discriminant of a quadratic equation is negative, how many real solutions does the equation have? a. 0 b. 1 c. 2 d. 3

0

Step-by-step explanation:

If the discriminant is negative then it will have 0 real number solutions. This is because the negative discriminant is above the x axis, so it will not have any x intercepts or solutions.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: