Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?

4 sec

Step-by-step explanation:

Let

x> distance the kitten runs before being caught by the puppy

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/20=(180-x)/25

25x=20(180-x)

25x=3,600-20x

25x+20x=3,600

x=3,600/45=80 m

t=d/v=80/20=4 sec

or

t=(180-80)/25=100/25=4 sec

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: