Abaseball is hit inside a baseball diamond with a length and width of 90 feet each. what is the probability that the ball will bounce on the pitchers mound, if the diameter of the mound is 18 feet? assume that the ball is equally likely to bounce anywhere in the infield. when applicable, leave your answer in terms of pie and include all necessary calculations.

90(squared) + 90 (squared) = C (squared)
(we use 90 because the base path is 90 ft long since the diamond is a square that makes all sides 90 ft long)
8100 + 8100 = c(squared)
16200 = c(squared)
we will get the square root of 16200 to get the diagonal length
C=127.3 ft, and since it is the diagonal distance we will device it to 2, to get the distance from the pitcher ro the 2nd base.
127.3/2 = 67.7 ft.
67.7 ft is the distance from the pitcher to the 2nd base.

Can't really understand try to post again