The equation h(t)=−16t2+115t+15 gives the height of a toy rocket, in feet, t seconds after it is launched from a platform. what is the height of the platform?

The given equation ⇒⇒⇒ h(t)=−16t² + 115t +15

Represents the height of a toy rocket, in feet, t seconds after it is launched from a platform.

So, at t = 0 ⇒⇒⇒ h(t)=−16 * (0)² + 115 * (0) +15 = 15

At t = 0 represents the height at the instant of launching the toy rocket and it is equal to the height of the platform.

∴ The height of the platform = 15 feet

A: 0.26 would be the answer

Distance=slopeslope is -2/4which equals-1/2the distance between these two points is -1/2