What is the following sum? assume x> =0 and y> =0 square root x^2y^2+2 square root x^3y^4+xy square root y

To solve this problem you must apply the proccedure shown below:   1. you have the following expression given in the problem above:   x^2y^2+2√(x^3y^4)+xy√y  2. therefore, you have:   x^2y^2+2(x^3y^4)^1/2+xy(y)^1/2  3. by the exponents properties, you obtain:   x^2y^2+2x^3/2y^4/2+xy^3/2  x^2y^2+2x^3/2y^2+xy^3/2  therefore, as you can see, the answer is: x^2y^2+2x^3/2y^2+xy^3/2