what  values  for  θ  (0  ≤  θ  ≤  2pie )  satisfy  the  equation?   2  sin  θ  cos  θ  + sqr3  cos  θ  =  0 a.) pie/2, 4pie/3, 3pie/2, 5pie/3 b.) pie/2, 3pie/4, 3pie/2, 5pie/3 c.) pie/2, 3pie/4, 3pie/2, 5pie/4 d.) pie/2, pie/4, 3pie/2, 5pie/3

Factor out the cosθ:
cosθ (2sinθ + sqrt3) = 0
Therefore, the only ways this can happen are if either cosθ = 0 or if (2sinθ + sqrt3) = 0
The first case, cosθ = 0 only at θ = pi/2, 3pi/2.
The second case, (2sinθ + sqrt3) = 0 simplifies to:
sinθ = (-sqrt3)/2
θ = 4pi/3, 5pi/3
Therefore the answer is A.