(1 pt)
three vertices of a rectangle are given. find the coordinates of the fourth vertex.
(–3, –3), (7, –3), (7, 2)
a.
(2, –3)
b.
(3, 2)
c.
(3, –2)
d.
(–3, 2)

The correct answer is choice D, or (-3, 2). We can tell because if we plot out the points, we go left 3, down 3 for (-3, -3), then right 7, down 3 for (7, -3), then right 7, up 2 for (7, 2), therefore the remaining point would have to be left -3, up 2, which is shown in choice D.
Hope that helped =)

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0 

The first one is the false statement