One number is 5 less than 2 times a second number. if 4 more than twice the first number is decreased by three times the second, the result is 6. find both numbers

Let
x> first number
y> second number

we know that
x=2y-5> equation 1
4+2x-3y=6 > 2x-3y=2> equation 2

substitute the equation 1 in equation 2
2*[2y-5]-3y=2> 4y-10-3y=2> y=2+10> y=12
x=2y-5> x=2*12-5> x=19

the answer is
first number is 19 and second number is 12