Noise in a quiet room is 500 times as intense as the threshold of sound. what is the decibel measurement for the quiet room?

27 db

Step-by-step explanation:

I₀ = threshold of sound = 1 x 10⁻¹² W/m²

I = intensity of sound in the room = 500 I₀ = 500 x 1 x 10⁻¹² =  500 x 10⁻¹² W/m²

β = Sound level in decibel in the quiet room

Sound level in decibel in the quiet room is given as

β = 10 log₁₀(I/I₀)

inserting the values

β = 10 log₁₀((500 x 10⁻¹²)/(1 x 10⁻¹²))

β = 27 db

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.