Which summation formula represents the series below? 13 + 9 + 5 + 1

The summation formula for the series is ⇒ 15n - 2n²

Step-by-step explanation:

* Lets check the series 13 , 9 , 5 , 1

∵ 9 - 13 = -4

∵ 5 - 9 = -4

∵ 1 - 5 = -4

∴ The series has a common difference

∴ It is an arithmetic series with first term a and constant difference d

* That means

- a1 = a , a2 = a + d , a3 = a + 2d , a4 = a + 3d

∴ an = a + (n - 1)d, where n is the position of the number in the series

* The sum of the arithmetic series can find by the rule

- Sn = n/2[2a + (n - 1)d], where n is the number of terms you want to add

* Lets use this rule in our problem

∵ Sn = n/2[2(13) + (n - 1)(-4)]

∴ Sn = n/2(26 + (-4n + 4)] ⇒ open the small bracket

∴ Sn = n/2[26 - 4n + 4] ⇒collect the like terms

∴ Sn = n/2[30 - 4n] ⇒ open the bracket

∴ Sn = (n/2)(30) - (n/2)(4n)

∴ Sn = 15n - 2n²

* The summation formula for the series is 15n - 2n²

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

squares, rhombus, rectangles