What are the zeros of the function y= (x+3)(x+2)(x-2) ?

If you are asking about the x-intercepts, then 
x=-3, x=-2, and x=2; this is because these numbers make the equation equal to 0 (or make y=0)
(3,0), (-2,0), and (2,0)

If you are asking about the y-intercept, then you make x=0, which makes the equation (3) times (2) times (-2) which equals -12. 
So, the y-intercept is -12.
(0,-12) 

7p=14 so then you would divide by p=2

2+1=3 that’s your answer