Using a table of value determine the solution to the equation below to the nearest fourth of a unit2^(-x) + 1 = 5^x + 2x= -1.50x= 2.50x= -0.50x= 0.75

For finding the solution to something like this, it makes sense to write a function of x that is zero at the solution value. That function might be obtained by subtracting the right side from the equation.
  f(x) = (2^-x +1) - (5^x +2)
Now, we want to find x so that f(x) = 0.

For the offered choices, we get
  f(-1.50) ≈ 1.74
  f(-0.50) ≈ -0.03
  f(0.75) ≈ -3.75
  f(2.50) ≈ -56.72

The obvious choice is
  x = -0.50