To solve e4 – 3x = (4/3)x + 9 by graphing, which equations should be graphed?   y = 0   y = (4/3)x + 9   y = e4 – 3x – (4/3) + 9   y = (4/3)x + 9 + e4 – 3x   y = e4 – 3x

We have to plot the system of equation as:

       and y= (4/3)x + 9

step-by-step solution:

We are asked to solve a equation as:

e^4-3 x = (4/3)x + 9.

i.e. it could be represented as:

y=e^4-3 x

and y=(4/3)x + 9.

it could also be written as:

e^4-3 x-(4/3)x - 9=0

To graph the following system we have to graph the equation as:

       and y= (4/3)x + 9

is there a question here?

step-by-step explanation: