Adata set is displayed using a dot plot. the range of the data is between 50 and 90, and the distribution is skewed left. which measure of center, the mean or median, is probably a better representation of the data? explain your reasoning. pls hurry

Answer with explanation:

→It is given that the distribution is skewed left, and the range of the data is between 50 and 90.

→When the distribution is skewed left

Mean < Median < Mode

→Since Mean and Median considers all the variate while calculating measure of center for a given set of Data set.When you calculate median you only count middle value among all the variate and when you calculate mean you use all the variate in the data set.

→When you will plot the graph of Left Skewed distribution you will find that Median is at the center of the left skewed graph than mean.So, Median is probably a better representation of the data set.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100