If equal and opposite charges Q were placed on the Earth and the Moon, what should be the value of Q to maintain the present orbit? Use these data: mass of Earth = 5.98×1024kgmass of Moon = 7.35×1022kgradius of orbit = 3.84×108m.

5.71 x 10^13 C.

Explanation:

We are given the following parameters or data or information and these data are going to help us in solving this particular Question or problem effectively and efficiently;

=> mass of Earth = 5.98 × 10^ 24kg, mass of Moon = 7.35 × 10^22 kg and the radius of orbit = 3.84 × 10^8m.

Recall that H =( G × m1 × m2) / r^2. where m1 and m2 are the masses of the two bodies amd r is the radius.

We will be making use of the formula below:

the value of Q to maintain the present orbit = √ { ( 7.35 × 10^22 ) × (5.98 × 10^24) × 4 × π × V.

the value of Q to maintain the present orbit = 5.71 x 10^13 C.

what are the options?

food and resources were plentiful.

women were encouraged to marry later in life so they could work in factories.