What is the equation of a line that is parallel to −2x+3y=−6 and passes through the point (−2, 0) ? enter your answer in the box.

y≈2/3x+4/3

As you have the paralel equation, you can have the pending from it by turning the equation to the form : y=mx+b, where m=2/3

3y=-6+2x

y=2/3x-(6/3) which is y=2/3x-2

from here you have m= 2/3

then to construct the equation you use the formula with the point (-2,0) which is y-y1= m (x-x1), where y1= 0 and x1=-2 and following the formula you have:

y-0= 2/3 (x-(-2)) which results into: y=2/3 (x+2) and you turn it into an explicit ecuation by multiplying y= 2/3x+4/3, this way you have y=mx+b equation formula

i think the answer is a and i hope this ; ))

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