In the lab, Ahmad has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A as Solution B. Solution A is 14 alcohol and Solution B is 10 alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 104 milliliters of pure alcohol?

200 milliliters

Explanation:

Let us assume the solution A  be X

And, the solution B be Y

So, according to the equation

Solution A = 3 times of Solution B

i.e X = 3 × Y (1)

And, the solution A = 0.14X

Solution B = 0.10Y =

So, now the equation is

14X + 10Y = 104,00 (2)

ANd, the X = 3Y

So, now we substitute it in equation (2)

14 × 3Y+ 10Y = 10,400

42Y + 10Y = 10,400

52Y = 10,400

Y = 200

So, X = 3 × 200 = 600

So, he use the 200 milliliters of solution B

Note: We assume the ratio of solution A and solution B is given in percentage form and we take the same

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explanation:

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