Prove: AB ≅ AC
Consider the diagram and proof by contradiction.
Given: △ABC with ∠B ≅ ∠C
Prove: AB ≅ AC
Triangle A B C is shown. Angles A B C and B C A are congruent.
It is given that ∠B ≅ ∠C. Assume AB and AC are not congruent. If AB > AC, then m∠C > m∠B by . If AC > AB, then m∠B > m∠C for the same reason. However, using the given statement and the definition of congruency, we know that m∠B = m∠C. Therefore, AB = AC and AB ≅ AC.
What is the missing reason in the proof?
converse of the triangle parts relationship theorem
substitution
definition of congruency
converse of the isosceles triangle theorem
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Consider the diagram and proof by contradiction.
Given: △ABC with ∠B ≅ ∠C
Prove: AB ≅ AC
Prove: AB ≅ AC
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