May consider a group g=({0,1},+)g=({0,1},+)where ++ will work as the xor operator like we work in boolean algebra. note here, that ‘00’ and ‘11’ are not the usual 0 and 1 that we work with everyday. the elements are called ‘00’ and ‘11’ and may not mean zero (nothing) and one (single). ‘00’ is the identity for the given binary operator +, meaning that any element operated with ‘00’ gets us that element itself. for a set ss in g′g′ having more elements than just {0,1}{0,1} the values for a+b∈sa+b∈s, such that a∈s,b∈sa∈s,b∈s, have to be first defined, only then can you determine the value of 1+11+1. the answer could possibly have been 22 if oanswer is25,000