What's the area of the figure. (show work . will give brainilest answer. ty)

To find the area of the triangle shown in the picture, we need to find the height and the base.

The length of the height should be:

cos45° = BC/AB

=> BC = AB · cos45° = 24 · cos45° = 12√2 (ft)

From the information provided, we can calculate ∠CAB which is 45°, therefore ΔABC is an isosceles triangle, meaning that BC = AC = 12√2 (ft)

The area of the figure is:

A = bh/2 = (12√2)²/2 = 144 (ft²)